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((x^0.3)/2)'The calculation above is a derivative of the function f (x)
((x^0.3)'*2-(x^0.3*(2)'))/(2^2)
(0.3*x^(0.3-1)*2-(x^0.3*(2)'))/(2^2)
(0.3*x^-0.7*2-(x^0.3*(2)'))/(2^2)
(0.3*x^-0.7*2-(x^0.3*0))/(2^2)
0.15*x^-0.7
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